Math Problem Solver

$$23 + 69=92$$

$$\begin{aligned} \overset{\mathtt{1}}{\mathtt{2}}\mathtt{3}\\ \mathtt{+\phantom{0}}\mathtt{6}\mathtt{9}\\ \hline \mathtt{9}\mathtt{2} \end{aligned}$$

$2$ is the digit in the $10^{0}$ place. $3 \times 10^{0} + 9 \times 10^{0} = 12 \times 10^{0} = 1 \times 10^{1} + 2 \times 10^{0}$.$1 \times 10^{1}$ carries to the $10^{1}$ place.

$9$ is the digit in the $10^{1}$ place. $1 \times 10^{1} + 2 \times 10^{1} + 6 \times 10^{1} = 9 \times 10^{1}$.