$\sqrt{\frac{\left[1 + \frac{\tan(20^\circ)}{\cot(65,5^\circ)}\right]}{\sin^2(65,5^\circ) - \frac{\tan(20^\circ) \cdot (1,4 + \cos(2 \cdot 65,5^\circ))}{2 \cdot \cot(65,5^\circ)}}}$
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.