0.175+40.2=((0.175)^3)/(b^2)*2
You asked:
Solve the equation \(0.175 + 40.2 = \frac{{0.175}^{3}}{{b}^{2}} \cdot 2\) for the variable \(b\).
MathBot Answer:
The solutions are given by the formula: \[b = \frac{7 \left(-1\right)^{k} \sqrt{22610}}{64600}\] where \(k\) is an integer in \(0 \le k < 2\).
There are \(2\) real solutions.
There are \(0\) solutions with nonzero imaginary part.
Real solutions: \[\begin{aligned}b &= \frac{7 \sqrt{22610}}{64600} \\&\approx 0.016293553\\b &= - \frac{7 \sqrt{22610}}{64600} \\&\approx -0.016293553\end{aligned}\]
The are no solutions with nonzero imaginary part.