3xy+9yz+3y
asked by guest on Mar 17, 2025 at 5:32 am
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MathBot Answer:
3xy+9yz+3y=3xy+9yz+3y\displaystyle 3 x y + 9 y z + 3 y = 3 x y + 9 y z + 3 y 3xy+9yz+3y=3xy+9yz+3y
3xy+9yz+3y=3y(x+3z+1)3 x y + 9 y z + 3 y = 3 y \left(x + 3 z + 1\right)3xy+9yz+3y=3y(x+3z+1)