work out the equation of the line which has a gradient of -2 and passes through the point (1,7).

asked by guest
on Apr 03, 2025 at 2:41 am



You asked:

Find an equation of the line through the point (1,7)(1, 7) with slope 2-2.

MathBot Answer:

Standard Form:

Ax+By+C=0\begin{aligned}Ax + By + C = 0\end{aligned}Slope=ABAB=21A=2,B=1\begin{aligned} \text{Slope} &= -\frac{A}{B} \\ -\frac{A}{B} &= \frac{-2}{1} \\ A =& 2, B = 1 \end{aligned}2x+1y+C=02(1)+1(7)+C=02+7+C=07+C=2C=9\begin{aligned}2 x + 1 y + C &= 0 \\ 2(1) + 1(7) + C &= 0 \\ 2 + 7 + C &= 0 \\ 7 + C &= -2 \\ C &= -9 \end{aligned}An equation of the line in standard form is: 2x+y9=02 x + y - 9 = 0.


Slope-Intercept Form:

y=mx+b\begin{aligned} y = mx+b\end{aligned}y=2x+b7=2×1+b7=2+bb=9\begin{aligned}y &= -2x + b \\ 7 &= -2 \times 1 + b \\ 7 &= -2 + b \\ b &= 9 \end{aligned}The slope-intercept form of the line is: y=2x+9y = - 2 x + 9.