\frac{x^2-5x-3}{(x+1)(x-1)(x-2)}

asked by guest
on Sep 16, 2024 at 12:48 pm



You asked:

Evaluate the expression: \(\frac{{x}^{2} - 5 x - 3}{\left(x + 1\right) \cdot \left(x - 1\right) \cdot \left(x - 2\right)}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{{x}^{2} - 5 x - 3}{\left(x + 1\right) \cdot \left(x - 1\right) \cdot \left(x - 2\right)} = \frac{x^{2} - 5 x - 3}{\left(x - 2\right) \left(x - 1\right) \left(x + 1\right)} \)

Expanded

\[\frac{{x}^{2} - 5 x - 3}{\left(x + 1\right) \cdot \left(x - 1\right) \cdot \left(x - 2\right)} = \frac{x^{2}}{x^{3} - 2 x^{2} - x + 2} - \frac{5 x}{x^{3} - 2 x^{2} - x + 2} - \frac{3}{x^{3} - 2 x^{2} - x + 2}\]

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