\lim _{x\to \:-\infty \:}\left(\frac{1-3e^x}{4+5e^x}\right)

asked by guest
on Jan 15, 2025 at 1:53 pm



You asked:

Evaluate the expression: \(\lim_{x \to -\infty}{\frac{1 - 3 {e}^{x}}{4 + 5 {e}^{x}}}\)

MathBot Answer:

\[\lim_{x \to -\infty}{\frac{1 - 3 {e}^{x}}{4 + 5 {e}^{x}}} = \frac{1}{4}\]

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).