Math Problem Solver

\[ 2\frac{4}{12} + 3\frac{2}{6} = \frac{17}{3} = 5.\overline{6} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{2}{1}\), \(\frac{4}{12}\), \(\frac{3}{1}\), and \(\frac{2}{6}\) is \(12\). \[ \begin{aligned} 2\frac{4}{12} + 3\frac{2}{6} &= \frac{2 \cdot 12}{1 \cdot 12} + \frac{4 \cdot 1}{12 \cdot 1} + \frac{3 \cdot 12}{1 \cdot 12} + \frac{2 \cdot 2}{6 \cdot 2} \\ &= \frac{24 + 4 + 36 + 4}{12} \\ &= \frac{68}{12} \\&= \frac{17}{3} \end{aligned} \]