3x^2+xy+3y^2=6, x-y=2

asked by guest
on Mar 25, 2025 at 1:19 pm



You asked:

Solve the system of equations:3x2+xy+3y2=6x−y=2\begin{aligned}3 {x}^{2} + x y + 3 {y}^{2} &= 6\\x - y &= 2\end{aligned}

MathBot Answer:

The system of equations has 22 solutions.

x=1−77,y=−1−77x = 1 - \frac{\sqrt{7}}{7}, y = -1 - \frac{\sqrt{7}}{7}x=77+1,y=−1+77x = \frac{\sqrt{7}}{7} + 1, y = -1 + \frac{\sqrt{7}}{7}
    • Axis Limits
    • min x
    • max x
    • min y
    • max y
  • Update Axis Limits
Close Controls

+ Submit Question