8.000= 2/n ⋅[1056+100⋅(n−1)]

asked by guest
on Nov 27, 2024 at 3:36 pm



You asked:

Solve the equation 8.000=2n(1056+100(n−1))8.000 = \frac{2}{n} \left(1056 + 100 \left(n - 1\right)\right) for the variable nn.

MathBot Answer:

The solution is: n=−23924=−9.9583‾n = - \frac{239}{24} = -9.958\overline{3}

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