8(2k+1+3k)
asked by guest on Mar 25, 2025 at 1:53 pm
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MathBot Answer:
8(2k+1+3k)=40k+8\displaystyle 8 \left(2 k + 1 + 3 k\right) = 40 k + 8 8(2k+1+3k)=40k+8
8(2k+1+3k)=40k+88 \left(2 k + 1 + 3 k\right) = 40 k + 88(2k+1+3k)=40k+8