factorize
2$x^{2}$/7 + x/14 + 4xy/21
You asked:
Factor the expression: \(\displaystyle \frac{2 \cdot {x}^{2}}{7} + \frac{x}{14} + \frac{4 x y}{21}\)
MathBot Answer:
The polynomial factors into the product: \[\frac{2 \cdot {x}^{2}}{7} + \frac{x}{14} + \frac{4 x y}{21} = \frac{x \left(12 x + 8 y + 3\right)}{42}\]