Math Problem Solver

\[ \frac{35}{42} + \frac{3}{1} + \frac{1}{5} = \frac{121}{30} = 4.0\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{35}{42}\), \(\frac{3}{1}\), and \(\frac{1}{5}\) is \(210\). \[ \begin{aligned} \frac{35}{42} + \frac{3}{1} + \frac{1}{5} &= \frac{35 \cdot 5}{42 \cdot 5} + \frac{3 \cdot 210}{1 \cdot 210} + \frac{1 \cdot 42}{5 \cdot 42} \\ &= \frac{175 + 630 + 42}{210} \\ &= \frac{847}{210} \\&= \frac{121}{30} \end{aligned} \]