log 1,5

asked by guest
on Oct 23, 2024 at 3:21 am



MathBot Answer:

The sum of \(\log\left( 1 \right)\) and \(5\) is:

\[\begin{aligned}&=\left(\log\left( 1 \right)\right) + \left(5\right) \\\\ &= \log{\left(1 \right)} + 5 \\\\ &= 5 \\\\\end{aligned}\]

The difference of \(\log\left( 1 \right)\) and \(5\) is:

\[\begin{aligned}&=\left(\log\left( 1 \right)\right) - \left(5\right) \\\\ &= -5 + \log{\left(1 \right)} \\\\ &= -5 \\\\\end{aligned}\]

The product of \(\log\left( 1 \right)\) and \(5\) is:

\[\begin{aligned}&=\left(\log\left( 1 \right)\right) \cdot \left(5\right) \\\\ &= 5 \log{\left(1 \right)} \\\\ &= 0 \\\\\end{aligned}\]

The quotient of \(\log\left( 1 \right)\) and \(5\) is:

\[\begin{aligned}&= \frac{\left(\log\left( 1 \right)\right)}{\left(5\right)} \\\\ &= \frac{\log{\left(1 \right)}}{5} \\\\ &= 0 \\\\\end{aligned}\]

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