e^4x-8=77^2x+2
You asked:
Investigate the equation: \({e}^{4} \cdot x - 8 = {77}^{2} \cdot x + 2\).
MathBot Answer:
The solution is: \[x = \frac{10}{\left(-77 + e^{2}\right) \left(77 + e^{2}\right)} \approx -0.001702301\]
\[\begin{aligned}x e^{4} - 8 &= 5929 x + 2\\x \left(-5929 + e^{4}\right) &= 10\\x &= \frac{10}{-5929 + e^{4}}\end{aligned}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).