y'+4ty=86

asked by guest
on Nov 15, 2024 at 8:35 am



You asked:

Investigate the equation: \(y^{\prime} + 4 t y = 86\).

MathBot Answer:

\[y{\left(t \right)} = \left(\frac{43 \sqrt{2} \sqrt{\pi} \operatorname{erfi}{\left(\sqrt{2} t \right)}}{2} + C_{1}\right) e^{- 2 t^{2}}\]

\(C_{1}\) is an arbitrary constant.


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).