(1/(√(2π)* 5.86))*e^((-(10.59-10.19)^2)/(2*34.35))

asked by guest
on Nov 17, 2024 at 8:17 am



You asked:

Evaluate the expression: \(\frac{1}{\sqrt{2 \cdot \pi} \cdot 5.86} \cdot {e}^{\frac{-{\left( 10.59 - 10.19 \right)}^{2}}{2 \cdot 34.35}}\)

MathBot Answer:

\[\frac{1}{\sqrt{2 \cdot \pi} \cdot 5.86} \cdot {e}^{\frac{-{\left( 10.59 - 10.19 \right)}^{2}}{2 \cdot 34.35}} = \frac{25 \sqrt{2}}{293 \sqrt{\pi} e^{\frac{8}{3435}}} \approx 0.06792051848046125787000772411229\]


\[\begin{aligned}\frac{1}{\sqrt{2 \cdot \pi} \cdot 5.86} \cdot {e}^{\frac{-{\left( 10.59 - 10.19 \right)}^{2}}{2 \cdot 34.35}}& = \frac{1}{\sqrt{2 \cdot \pi} \cdot \left(5 + \frac{86}{100}\right)} \cdot e^{- \cdot \left(10 + \frac{59}{100} - \left(10 + \frac{19}{100}\right)\right)^{2} \cdot \frac{1}{2 \cdot \left(34 + \frac{35}{100}\right)}}\\& = \frac{1}{\sqrt{2} \cdot \sqrt{\pi} \cdot \left(5 + \frac{86}{100}\right)} \cdot e^{- \cdot \left(10 + \frac{59}{100} - \left(10 + \frac{19}{100}\right)\right)^{2} \cdot \frac{1}{2 \cdot \left(34 + \frac{35}{100}\right)}}\\& = \frac{1}{\sqrt{2} \cdot \sqrt{\pi} \cdot \left(5 + \frac{43}{50}\right)} \cdot e^{- \cdot \left(10 + \frac{59}{100} - \left(10 + \frac{19}{100}\right)\right)^{2} \cdot \frac{1}{2 \cdot \left(34 + \frac{35}{100}\right)}}\\& = \frac{1}{\sqrt{2} \cdot \sqrt{\pi} \cdot \frac{293}{50}} \cdot e^{- \cdot \left(10 + \frac{59}{100} - \left(10 + \frac{19}{100}\right)\right)^{2} \cdot \frac{1}{2 \cdot \left(34 + \frac{35}{100}\right)}}\\& = \frac{1}{\frac{293}{50} \cdot \sqrt{2} \cdot \sqrt{\pi}} \cdot e^{- \cdot \left(10 + \frac{59}{100} - \left(10 + \frac{19}{100}\right)\right)^{2} \cdot \frac{1}{2 \cdot \left(34 + \frac{35}{100}\right)}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot e^{- \cdot \left(10 + \frac{59}{100} - \left(10 + \frac{19}{100}\right)\right)^{2} \cdot \frac{1}{2 \cdot \left(34 + \frac{35}{100}\right)}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot e^{- \cdot \left(10 + \frac{59}{100} - \frac{1019}{100}\right)^{2} \cdot \frac{1}{2 \cdot \left(34 + \frac{35}{100}\right)}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot e^{- \cdot \left(\frac{1059}{100} - \frac{1019}{100}\right)^{2} \cdot \frac{1}{2 \cdot \left(34 + \frac{35}{100}\right)}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot e^{- \cdot \left(\frac{2}{5}\right)^{2} \cdot \frac{1}{2 \cdot \left(34 + \frac{35}{100}\right)}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot e^{- \cdot \frac{4}{25} \cdot \frac{1}{2 \cdot \left(34 + \frac{35}{100}\right)}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot e^{- \cdot \frac{4}{25} \cdot \frac{1}{2 \cdot \left(34 + \frac{7}{20}\right)}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot e^{- \cdot \frac{4}{25} \cdot \frac{1}{2 \cdot \frac{687}{20}}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot e^{- \cdot \frac{4}{25} \cdot \frac{1}{\frac{687}{10}}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot e^{- \frac{8}{3435}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot \frac{1}{e^{\frac{8}{3435}}}\\& = \frac{25}{293} \cdot \sqrt{2} \cdot \frac{1}{\sqrt{\pi}} \cdot e^{- \frac{8}{3435}}\end{aligned}\]


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).