ln 𝑒^0.014𝑡 = ln 20

asked by guest
on Jan 21, 2025 at 10:06 pm



You asked:

Investigate the equation: \(\ln\left( {e}^{0.014} t \right) = \ln\left( 20 \right)\).

MathBot Answer:

The solution is: \[t = \frac{20}{e^{\frac{7}{500}}} \approx 19.721951\]


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).