ln 𝑒^0.014𝑡 = ln 20
You asked:
Investigate the equation: \(\ln\left( {e}^{0.014} t \right) = \ln\left( 20 \right)\).
MathBot Answer:
The solution is: \[t = \frac{20}{e^{\frac{7}{500}}} \approx 19.721951\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).