e^(-2*Ln(x))
You asked:
Evaluate the expression: \({e}^{-2 \ln\left( x \right)}\)
MathBot Answer:
\[{e}^{-2 \ln\left( x \right)} = \frac{1}{x^{2}}\]
e^(-2*Ln(x))
You asked:
MathBot Answer:
\[{e}^{-2 \ln\left( x \right)} = \frac{1}{x^{2}}\]