(3600*6500)/x=(160+7500/(44+x))*240*10

asked by guest
on Mar 23, 2025 at 1:13 pm



You asked:

Solve the equation 3600⋅6500x=(160+750044+x)⋅240⋅10\frac{3600 \cdot 6500}{x} = \left(160 + \frac{7500}{44 + x}\right) \cdot 240 \cdot 10 for the variable xx.

MathBot Answer:

The 2 solutions to the equation are: x=−47932+43160932≈38.93221x=−47932−43160932≈−68.86971\begin{aligned}x &= - \frac{479}{32} + \frac{43 \sqrt{1609}}{32} \approx 38.93221\\x &= - \frac{479}{32} - \frac{43 \sqrt{1609}}{32} \approx -68.86971\end{aligned}

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