x ^ { 3 } +2x ^ { 2 } -x-2 \div x-1
asked by guest on Mar 26, 2025 at 8:43 pm
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x3+2x2−x−2x−1=x3+2x2−x−1−2x\displaystyle {x}^{3} + 2 {x}^{2} - x - \frac{2}{x} - 1 = x^{3} + 2 x^{2} - x - 1 - \frac{2}{x} x3+2x2−x−x2−1=x3+2x2−x−1−x2
x3+2x2−x−2x−1=x4+2x3−x2−x−2x{x}^{3} + 2 {x}^{2} - x - \frac{2}{x} - 1 = \frac{x^{4} + 2 x^{3} - x^{2} - x - 2}{x}x3+2x2−x−x2−1=xx4+2x3−x2−x−2