Find u by integrating
dz/{2z(zu-c) +c} = du/{-2u(zu-c) }
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
Find u by integrating
dz/{2z(zu-c) +c} = du/{-2u(zu-c) }
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.