(4.46 x 10^-3)±√(4.46 x 10^-3)²-4(4)(-8.92 x 10^-3)

asked by guest
on Nov 20, 2024 at 5:25 am



You asked:

Evaluate the expression: 4.46⋅10−3±4.46⋅10−32−4⋅4⋅−8.92⋅10−34.46 \cdot {10}^{-3} \pm {\sqrt{4.46 \cdot {10}^{-3}}}^{2} - 4 \cdot 4 \cdot -8.92 \cdot {10}^{-3}

MathBot Answer:

This question involves the ±\pm operator. There are 22 variations to solve.

Variation 11 of 22

4+46⋅11001000+(4+46⋅11001000)2−−4⋅4⋅(8+92⋅1100)1000=379125000 \frac{4 + 46 \cdot \frac{1}{100}}{1000} + \left(\sqrt{\frac{4 + 46 \cdot \frac{1}{100}}{1000}}\right)^{2} - -\frac{4 \cdot 4 \cdot \left(8 + 92 \cdot \frac{1}{100}\right)}{1000} = \frac{3791}{25000}

Variation 22 of 22

4+46⋅11001000−(4+46⋅11001000)2−−4⋅4⋅(8+92⋅1100)1000=4463125 \frac{4 + 46 \cdot \frac{1}{100}}{1000} - \left(\sqrt{\frac{4 + 46 \cdot \frac{1}{100}}{1000}}\right)^{2} - -\frac{4 \cdot 4 \cdot \left(8 + 92 \cdot \frac{1}{100}\right)}{1000} = \frac{446}{3125}

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