5(2-x)x+5x²-3x=4(x-2)+27
You asked:
Solve the equation \(5 \cdot \left(2 - x\right) \cdot x + 5 \cdot {x}^{2} - 3 x = 4 \cdot \left(x - 2\right) + 27\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{19}{3} = 6.\overline{3}\]
\[\begin{aligned}5 \cdot \left(2 - x\right) \cdot x + 5 \cdot {x}^{2} - 3 x &= 4 \cdot \left(x - 2\right) + 27\\7 x &= 4 x + 19\\3 x &= 19\\x &= \frac{19}{3}\end{aligned}\]