4b^3 - 6b^2 + 1 = 0
You asked:
Solve the equation \(4 \cdot {b}^{3} - 6 \cdot {b}^{2} + 1 = 0\) for the variable \(b\).
MathBot Answer:
The 3 solutions to the equation are: \[\begin{aligned}b &= \frac{1}{2} = 0.5\\b &= \frac{1}{2} - \frac{\sqrt{3}}{2} \approx -0.3660254\\b &= \frac{1}{2} + \frac{\sqrt{3}}{2} \approx 1.3660254\end{aligned}\]