$8/6^{2x-1}$ = $25/4^{2x}$
You asked:
Solve the equation \(\frac{8}{{6}^{2 x - 1}} = \frac{25}{{4}^{2 x}}\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = - \frac{- 2 \log{\left(5 \right)} + \log{\left(48 \right)}}{2 \left(- \log{\left(6 \right)} + 2 \log{\left(2 \right)}\right)} \approx 0.80441593\]