√3√3+4√12

asked by guest
on Nov 27, 2024 at 10:51 am



You asked:

Evaluate the expression: 3⋅3+412\sqrt{3} \cdot \sqrt{3} + 4 \sqrt{12}

MathBot Answer:

3⋅3+412=3+83≈16.85640646055101834821957073204698\sqrt{3} \cdot \sqrt{3} + 4 \sqrt{12} = 3 + 8 \sqrt{3} \approx 16.85640646055101834821957073204698

3⋅3+412=3⋅3+4⋅12=3+4⋅12=3+4⋅2⋅3=3+8⋅3\begin{aligned}\sqrt{3} \cdot \sqrt{3} + 4 \sqrt{12}&=\sqrt{3} \cdot \sqrt{3} + 4 \cdot \sqrt{12}\\&=3 + 4 \cdot \sqrt{12}\\&=3 + 4 \cdot 2 \cdot \sqrt{3}\\&=3 + 8 \cdot \sqrt{3}\end{aligned}

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