2ln(5)+4ln(3)-17ln(2)

asked by guest
on Jan 22, 2025 at 9:04 pm



You asked:

Evaluate the expression: 2ln⁡(5)+4ln⁡(3)−17ln⁡(2)2 \ln\left( 5 \right) + 4 \ln\left( 3 \right) - 17 \ln\left( 2 \right)

MathBot Answer:

2ln⁡(5)+4ln⁡(3)−17ln⁡(2)=−17log⁡(2)+2log⁡(5)+4log⁡(3)≈−4.170177089978430745310446450646522 \ln\left( 5 \right) + 4 \ln\left( 3 \right) - 17 \ln\left( 2 \right) = - 17 \log{\left(2 \right)} + 2 \log{\left(5 \right)} + 4 \log{\left(3 \right)} \approx -4.17017708997843074531044645064652

2ln⁡(5)+4ln⁡(3)−17ln⁡(2)=2⋅log⁡(5)+4⋅log⁡(3)−17⋅log⁡(2)=(2⋅log⁡(5)+4⋅log⁡(3))−17⋅log⁡(2)=−17⋅log⁡(2)+2⋅log⁡(5)+4⋅log⁡(3)\begin{aligned}2 \ln\left( 5 \right) + 4 \ln\left( 3 \right) - 17 \ln\left( 2 \right)&=2 \cdot \log{\left(5 \right)} + 4 \cdot \log{\left(3 \right)} - 17 \cdot \log{\left(2 \right)}\\&=\left(2 \cdot \log{\left(5 \right)} + 4 \cdot \log{\left(3 \right)}\right) - 17 \cdot \log{\left(2 \right)}\\&=-17 \cdot \log{\left(2 \right)} + 2 \cdot \log{\left(5 \right)} + 4 \cdot \log{\left(3 \right)}\end{aligned}

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