6x-(3/2)x+1/2=3x+1
You asked:
Solve the equation \(6 x - \frac{3}{2} \cdot x + \frac{1}{2} = 3 x + 1\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{1}{3} = 0.\overline{3}\]
\[\begin{aligned}6 x - \frac{3}{2} \cdot x + \frac{1}{2} &= 3 x + 1\\\frac{9 x}{2} + \frac{1}{2} &= 3 x + 1\\\frac{3 x}{2} &= \frac{1}{2}\\x &= \frac{1}{3}\end{aligned}\]