square root x-2 / 2x+1 = p/q make x the subject
You asked:
Solve the equation \[\sqrt{x - \frac{2}{2 x} + 1} = \frac{p}{q}\] for the unknown \(x\).
MathBot Answer:
$$\begin{aligned}x &= \frac{\left(p - q\right) \left(p + q\right)}{2 q^{2}} - \frac{\sqrt{p^{4} - 2 p^{2} q^{2} + 5 q^{4}}}{2 q^{2}}\\x &= \frac{\left(p - q\right) \left(p + q\right)}{2 q^{2}} + \frac{\sqrt{p^{4} - 2 p^{2} q^{2} + 5 q^{4}}}{2 q^{2}}\end{aligned}$$ and \(x \neq 0\)