Math Problem Solver

\[ 7 + 2 + \frac{1}{3} = \frac{28}{3} = 9.\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{7}{1}\), \(\frac{2}{1}\), and \(\frac{1}{3}\) is \(3\). \[ \begin{aligned} 7 + 2 + \frac{1}{3} &= \frac{7 \cdot 3}{1 \cdot 3} + \frac{2 \cdot 3}{1 \cdot 3} + \frac{1 \cdot 1}{3 \cdot 1} \\ &= \frac{21 + 6 + 1}{3} \\ &= \frac{28}{3} \end{aligned} \]