$$\int(3x+5)/(x^2 +3x-18)$$

asked by guest
on Oct 22, 2024 at 12:23 am



You asked:

Evaluate the integral: \(\int{\frac{3 x + 5}{{x}^{2} + 3 x - 18}}dx\)

MathBot Answer:

Antiderivative

\[\int{\frac{3 x + 5}{{x}^{2} + 3 x - 18}}dx = \frac{13 \log{\left(6 + x \right)}}{9} + \frac{14 \log{\left(-3 + x \right)}}{9} + C\]