(3k-5h)(-h-7k)
asked by guest on Apr 02, 2025 at 9:59 pm
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MathBot Answer:
(3k−5h)(−h−7k)=(−5h+3k)(−h−7k)\displaystyle \left(3 k - 5 h\right) \left(-h - 7 k\right) = \left(- 5 h + 3 k\right) \left(- h - 7 k\right) (3k−5h)(−h−7k)=(−5h+3k)(−h−7k)
(3k−5h)(−h−7k)=5h2+32hk−21k2\left(3 k - 5 h\right) \left(-h - 7 k\right) = 5 h^{2} + 32 h k - 21 k^{2}(3k−5h)(−h−7k)=5h2+32hk−21k2
(3k−5h)(−h−7k)=(5h−3k)(h+7k)\left(3 k - 5 h\right) \left(-h - 7 k\right) = \left(5 h - 3 k\right) \left(h + 7 k\right)(3k−5h)(−h−7k)=(5h−3k)(h+7k)