(2+3i)(2-3i)/3-4i

asked by guest
on Mar 13, 2025 at 11:45 am



You asked:

Evaluate the expression: (2+3i)(2−3i)3−4i\frac{\left(2 + 3 i\right) \left(2 - 3 i\right)}{3} - 4 i

MathBot Answer:

Evaluated



(2+3i)(2−3i)3−4i=(2−3i)(2+3i)3−4i\displaystyle \frac{\left(2 + 3 i\right) \left(2 - 3 i\right)}{3} - 4 i = \frac{\left(2 - 3 i\right) \left(2 + 3 i\right)}{3} - 4 i

Expanded

(2+3i)(2−3i)3−4i=133−4i\frac{\left(2 + 3 i\right) \left(2 - 3 i\right)}{3} - 4 i = \frac{13}{3} - 4 i

Factored

(2+3i)(2−3i)3−4i=13−12i3\frac{\left(2 + 3 i\right) \left(2 - 3 i\right)}{3} - 4 i = \frac{13 - 12 i}{3}

ii is the imaginary unit, defined as i2=−1i^2 = -1.

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