y=2^x find x
asked by guest on Mar 30, 2025 at 10:05 pm
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MathBot Answer:
x=log(y)log(2)∧−∞<x∧x<∞x = \frac{\log{\left(y \right)}}{\log{\left(2 \right)}} \wedge -\infty < x \wedge x < \inftyx=log(2)log(y)∧−∞<x∧x<∞