y=2^x find x

asked by guest
on Mar 30, 2025 at 10:05 pm



You asked:

Solve the equation y=2xy = {2}^{x} for the unknown xx.

MathBot Answer:

x=log(y)log(2)<xx<x = \frac{\log{\left(y \right)}}{\log{\left(2 \right)}} \wedge -\infty < x \wedge x < \infty