10/(3x-2)-3
asked by guest on Jan 28, 2025 at 2:45 pm
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MathBot Answer:
103x−2−3=−3+103x−2\displaystyle \frac{10}{3 x - 2} - 3 = -3 + \frac{10}{3 x - 2} 3x−210−3=−3+3x−210
103x−2−3=−9x−163x−2\frac{10}{3 x - 2} - 3 = - \frac{9 x - 16}{3 x - 2}3x−210−3=−3x−29x−16