sin(π/2-nπ/2)

asked by guest
on Nov 15, 2024 at 8:17 pm



You asked:

Evaluate the expression: \(\sin\left( \frac{\pi}{2} - \frac{n \cdot \pi}{2} \right)\)

MathBot Answer:

\[\sin\left( \frac{\pi}{2} - \frac{n \cdot \pi}{2} \right) = \cos{\left(\frac{n \pi}{2} \right)}\]

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