p^2-q^2=√6, p+q=√3 then p-q= ?
You asked:
Given the following equations: \[\begin{aligned}{p}^{2} - {q}^{2} &= \sqrt{6}\\ p + q &= \sqrt{3}\end{aligned}\] Evaluate \(p - q\).
MathBot Answer:
The system of equations has one solution.
\[p = \frac{\sqrt{2}}{2} + \frac{\sqrt{3}}{2}, q = - \frac{\sqrt{2}}{2} + \frac{\sqrt{3}}{2}\]
By substituting these values into the expression, we find that: $$\begin{aligned}p - q &= \sqrt{2} \approx 1.41421\end{aligned}$$