p^2-q^2=√6, p+q=√3 then p-q= ?

asked by guest
on Jan 10, 2025 at 3:12 am



MathBot Answer:

The system of equations has one solution.

p=22+32,q=−22+32p = \frac{\sqrt{2}}{2} + \frac{\sqrt{3}}{2}, q = - \frac{\sqrt{2}}{2} + \frac{\sqrt{3}}{2}

By substituting these values into the expression, we find that: p−q=2≈1.41421\begin{aligned}p - q &= \sqrt{2} \approx 1.41421\end{aligned}

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