(√8a + √6a)^2

asked by guest
on Jan 22, 2025 at 3:06 am



You asked:

Evaluate the expression: \({\left( \sqrt{8} \cdot a + \sqrt{6} \cdot a \right)}^{2}\)

MathBot Answer:

Evaluated



\(\displaystyle {\left( \sqrt{8} \cdot a + \sqrt{6} \cdot a \right)}^{2} = \left(\sqrt{6} a + 2 \sqrt{2} a\right)^{2} \)


Expanded

\[{\left( \sqrt{8} \cdot a + \sqrt{6} \cdot a \right)}^{2} = 8 \sqrt{3} a^{2} + 14 a^{2}\]


Factored

\[{\left( \sqrt{8} \cdot a + \sqrt{6} \cdot a \right)}^{2} = a^{2} \left(\sqrt{6} + 2 \sqrt{2}\right)^{2}\]