Math Problem Solver

\[ 2\frac{7}{8} + 3\frac{1}{3} = \frac{149}{24} = 6.208\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{2}{1}\), \(\frac{7}{8}\), \(\frac{3}{1}\), and \(\frac{1}{3}\) is \(24\). \[ \begin{aligned} 2\frac{7}{8} + 3\frac{1}{3} &= \frac{2 \cdot 24}{1 \cdot 24} + \frac{7 \cdot 3}{8 \cdot 3} + \frac{3 \cdot 24}{1 \cdot 24} + \frac{1 \cdot 8}{3 \cdot 8} \\ &= \frac{48 + 21 + 72 + 8}{24} \\ &= \frac{149}{24} \end{aligned} \]