4((10-27*2)/(1+1*5))/(6/3)

asked by guest
on Apr 02, 2025 at 6:44 pm



You asked:

Evaluate the expression: 4⋅10−27⋅21+1⋅563\frac{4 \cdot \frac{10 - 27 \cdot 2}{1 + 1 \cdot 5}}{\frac{6}{3}}

MathBot Answer:

4⋅10−27⋅21+1⋅563=−443=−14.6‾\frac{4 \cdot \frac{10 - 27 \cdot 2}{1 + 1 \cdot 5}}{\frac{6}{3}} = - \frac{44}{3} = -14.\overline{6}

4⋅10−27⋅21+1⋅563=4⋅10−541+1⋅563=4⋅−441+1⋅563=4⋅−441+563=4⋅−44663=4⋅−22363=−88363=−8832=−443\begin{aligned}\frac{4 \cdot \frac{10 - 27 \cdot 2}{1 + 1 \cdot 5}}{\frac{6}{3}}&=\frac{4 \cdot \frac{10 - 54}{1 + 1 \cdot 5}}{\frac{6}{3}}\\&=\frac{4 \cdot \frac{-44}{1 + 1 \cdot 5}}{\frac{6}{3}}\\&=\frac{4 \cdot \frac{-44}{1 + 5}}{\frac{6}{3}}\\&=\frac{4 \cdot \frac{-44}{6}}{\frac{6}{3}}\\&=\frac{4 \cdot \frac{-22}{3}}{\frac{6}{3}}\\&=\frac{\frac{-88}{3}}{\frac{6}{3}}\\&=\frac{\frac{-88}{3}}{2}\\&=\frac{-44}{3}\end{aligned}

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