Math Problem Solver

\[ \frac{1}{18} + \frac{1}{24} + \frac{1}{36} = \frac{1}{8} = 0.125 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{18}\), \(\frac{1}{24}\), and \(\frac{1}{36}\) is \(72\). \[ \begin{aligned} \frac{1}{18} + \frac{1}{24} + \frac{1}{36} &= \frac{1 \cdot 4}{18 \cdot 4} + \frac{1 \cdot 3}{24 \cdot 3} + \frac{1 \cdot 2}{36 \cdot 2} \\ &= \frac{4 + 3 + 2}{72} \\ &= \frac{9}{72} \\&= \frac{1}{8} \end{aligned} \]