(√7/4)(4/4)+(3/√7)(4/√7)

asked by guest
on Nov 26, 2024 at 12:51 am



You asked:

Evaluate the expression: 74⋅44+37⋅47\frac{\sqrt{7}}{4} \cdot \frac{4}{4} + \frac{3}{\sqrt{7}} \cdot \frac{4}{\sqrt{7}}

MathBot Answer:

74⋅44+37⋅47=74+127≈2.37572354205186193333968965269553\frac{\sqrt{7}}{4} \cdot \frac{4}{4} + \frac{3}{\sqrt{7}} \cdot \frac{4}{\sqrt{7}} = \frac{\sqrt{7}}{4} + \frac{12}{7} \approx 2.37572354205186193333968965269553

74⋅44+37⋅47=7⋅14⋅44+3⋅17⋅4⋅17=14⋅7⋅44+3⋅17⋅4⋅17=14⋅7+3⋅17⋅4⋅17=14⋅7+3⋅17⋅7⋅4⋅17=14⋅7+3⋅17⋅7⋅47⋅7=14⋅7+37⋅7⋅47⋅7=14⋅7+127=127+14⋅7\begin{aligned}\frac{\sqrt{7}}{4} \cdot \frac{4}{4} + \frac{3}{\sqrt{7}} \cdot \frac{4}{\sqrt{7}}&=\sqrt{7} \cdot \frac{1}{4} \cdot \frac{4}{4} + 3 \cdot \frac{1}{\sqrt{7}} \cdot 4 \cdot \frac{1}{\sqrt{7}}\\&=\frac{1}{4} \cdot \sqrt{7} \cdot \frac{4}{4} + 3 \cdot \frac{1}{\sqrt{7}} \cdot 4 \cdot \frac{1}{\sqrt{7}}\\&=\frac{1}{4} \cdot \sqrt{7} + 3 \cdot \frac{1}{\sqrt{7}} \cdot 4 \cdot \frac{1}{\sqrt{7}}\\&=\frac{1}{4} \cdot \sqrt{7} + 3 \cdot \frac{1}{7} \cdot \sqrt{7} \cdot 4 \cdot \frac{1}{\sqrt{7}}\\&=\frac{1}{4} \cdot \sqrt{7} + 3 \cdot \frac{1}{7} \cdot \sqrt{7} \cdot \frac{4}{7} \cdot \sqrt{7}\\&=\frac{1}{4} \cdot \sqrt{7} + \frac{3}{7} \cdot \sqrt{7} \cdot \frac{4}{7} \cdot \sqrt{7}\\&=\frac{1}{4} \cdot \sqrt{7} + \frac{12}{7}\\&=\frac{12}{7} + \frac{1}{4} \cdot \sqrt{7}\end{aligned}

+ Submit Question