y'+2xy= $e^{x ^2}$ $x^{3}$ $y^{2}$
You asked:
Investigate the equation: \(y^{\prime} + 2 x y = {e}^{{x}^{2}} {x}^{3} {y}^{2}\).
MathBot Answer:
\[y{\left(x \right)} = \frac{4 e^{- x^{2}}}{- x^{4} + C_{1}}\]
\(C_{1}\) is an arbitrary constant.
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).