x+y/4 -9/2z when x=2 y=4 and z=-3
asked by guest on Jan 08, 2025 at 8:08 am
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MathBot Answer:
x+y4−92z=92x + \frac{y}{4} - \frac{9}{2 z} = \frac{9}{2}x+4y−2z9=29
x+y4−92z=−92(−3)+44+2=−92(−3)+1+2=−−923+1+2=1+2+32=92\begin{aligned}x + \frac{y}{4} - \frac{9}{2 z}&=\frac{-9}{2 \left(-3\right)} + \frac{4}{4} + 2\\&=\frac{-9}{2 \left(-3\right)} + 1 + 2\\&=\frac{-- \frac{9}{2}}{3} + 1 + 2\\&=1 + 2 + \frac{3}{2}\\&=\frac{9}{2}\end{aligned}x+4y−2z9=2(−3)−9+44+2=2(−3)−9+1+2=3−−29+1+2=1+2+23=29