47(mod 5)
You asked:
Evaluate \(47\) modulo \(5\)
MathBot Answer:
\[47 \bmod 5 = 2\]
Given two numbers \(a\) and \(n\), \(a\) modulo \(n\) (often written \(a \bmod n\)) is the remainder when \(a\) is divided by \(n\).
\(\dfrac{47}{5} = 9\) with remainder \(2\)
Therefore \(47 \bmod 5 = 2\)