1 - 4*n - 4*n^2

factorize

asked by guest
on Jan 28, 2025 at 3:28 pm



You asked:

Factor the expression: 14n4n2\displaystyle 1 - 4 n - 4 {n}^{2}

MathBot Answer:

Factorization over the real numbers:

4(n+(1222))(n+(12+22))- 4 \left(n + \left(\frac{1}{2} - \frac{\sqrt{2}}{2}\right)\right) \left(n + \left(\frac{1}{2} + \frac{\sqrt{2}}{2}\right)\right)