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log4(x+y) =2log4(X)

log4(y)=log4(3)+log4(X)

asked by guest
on Mar 28, 2025 at 9:34 pm



You asked:

Solve the system of equations:log⁡4(x+y)=2log⁡4(X)log⁡4(y)=log⁡4(3)+log⁡4(X)\begin{aligned}\log_{4}\left( x + y \right) &= 2 \log_{4}\left( X \right)\\\log_{4}\left( y \right) &= \log_{4}\left( 3 \right) + \log_{4}\left( X \right)\end{aligned}

MathBot Answer:

The system of equations has infinitely many solutions.

X=y3x=y29−yy={y}∖{0}\begin{aligned}X &= \frac{y}{3}\\x &= \frac{y^{2}}{9} - y\\y &= \left\{y\right\} \setminus \left\{0\right\}\end{aligned}

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