24x + 18(63/50)+33=0

asked by guest
on Nov 26, 2024 at 10:32 am



You asked:

Solve the equation \(24 x + 18 \cdot \frac{63}{50} + 33 = 0\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = - \frac{58}{25} = -2.32\]


\[\begin{aligned}24 x + 18 \cdot \frac{63}{50} + 33 &= 0\\24 x + \frac{1392}{25} &= 0\\24 x &= - \frac{1392}{25}\\x &= - \frac{58}{25}\end{aligned}\]