$$\int_{-2}^{3}(-x^2+x+6) dx$$

asked by guest
on Nov 26, 2024 at 3:42 pm



You asked:

Evaluate the integral: \(\int_{-2}^{3}{-{x}^{2} + x + 6}dx\)

MathBot Answer:

Definite integral

\[\int_{-2}^{3}{-{x}^{2} + x + 6}dx = \frac{125}{6} = 20.8\overline{3}\]